Acid / base dilution: practice problems Work out the stock molarity, the acid aliquot, and the water volume. Every answer here is computed by the same tested calculator the rest of the site uses, so a solution can never drift away from the maths.
Problem 1 Acid / base dilution Work out the stock molarity, the acid aliquot, and the water volume.
Label concentration (%w/w): 37 Density (g/mL): 1.19 Molar mass (g/mol): 36.46 Target concentration: 4 M Final volume: 750 mL Show the answer and the working Measure 248.4 mL of the 37% stock (≈ 12.08 M) and dilute to 750 mL total.
Derive Stock molarity: M = (10 · %w/w · ρ) / MW Substitute label: M = (10 · 37 · 1.19) / 36.46 = 12.08 M Solve for Aliquot: V₁ = (C₂ · V₂) / C₁ Substitute: V₁ = (4 M · 750 mL) / (12.08 M) = 248.4 mL Diluent: V₂ − V₁ = 501.6 mL Open this in the calculator to change the numbers.
Problem 2 Acid / base dilution Work out the stock molarity, the acid aliquot, and the water volume.
Label concentration (%w/w): 98 Density (g/mL): 1.84 Molar mass (g/mol): 98.08 Target concentration: 1 M Final volume: 750 mL Show the answer and the working Measure 40.79 mL of the 98% stock (≈ 18.38 M) and dilute to 750 mL total.
Derive Stock molarity: M = (10 · %w/w · ρ) / MW Substitute label: M = (10 · 98 · 1.84) / 98.08 = 18.38 M Solve for Aliquot: V₁ = (C₂ · V₂) / C₁ Substitute: V₁ = (1 M · 750 mL) / (18.38 M) = 40.79 mL Diluent: V₂ − V₁ = 709.2 mL Open this in the calculator to change the numbers.
Problem 3 Acid / base dilution Work out the stock molarity, the acid aliquot, and the water volume.
Label concentration (%w/w): 37 Density (g/mL): 1.19 Molar mass (g/mol): 36.46 Target concentration: 4 M Final volume: 100 mL Show the answer and the working Measure 33.12 mL of the 37% stock (≈ 12.08 M) and dilute to 100 mL total.
Derive Stock molarity: M = (10 · %w/w · ρ) / MW Substitute label: M = (10 · 37 · 1.19) / 36.46 = 12.08 M Solve for Aliquot: V₁ = (C₂ · V₂) / C₁ Substitute: V₁ = (4 M · 100 mL) / (12.08 M) = 33.12 mL Diluent: V₂ − V₁ = 66.88 mL Open this in the calculator to change the numbers.
Problem 4 Acid / base dilution Work out the stock molarity, the acid aliquot, and the water volume.
Label concentration (%w/w): 75 Density (g/mL): 1.84 Molar mass (g/mol): 98.08 Target concentration: 0.5 M Final volume: 200 mL Show the answer and the working Measure 7.107 mL of the 75% stock (≈ 14.07 M) and dilute to 200 mL total.
Derive Stock molarity: M = (10 · %w/w · ρ) / MW Substitute label: M = (10 · 75 · 1.84) / 98.08 = 14.07 M Solve for Aliquot: V₁ = (C₂ · V₂) / C₁ Substitute: V₁ = (0.5 M · 200 mL) / (14.07 M) = 7.107 mL Diluent: V₂ − V₁ = 192.9 mL Open this in the calculator to change the numbers.
Problem 5 Acid / base dilution Work out the stock molarity, the acid aliquot, and the water volume.
Label concentration (%w/w): 75 Density (g/mL): 1.19 Molar mass (g/mol): 36.46 Target concentration: 1 M Final volume: 200 mL Show the answer and the working Measure 8.17 mL of the 75% stock (≈ 24.48 M) and dilute to 200 mL total.
Derive Stock molarity: M = (10 · %w/w · ρ) / MW Substitute label: M = (10 · 75 · 1.19) / 36.46 = 24.48 M Solve for Aliquot: V₁ = (C₂ · V₂) / C₁ Substitute: V₁ = (1 M · 200 mL) / (24.48 M) = 8.17 mL Diluent: V₂ − V₁ = 191.8 mL Open this in the calculator to change the numbers.
Problem 6 Acid / base dilution Work out the stock molarity, the acid aliquot, and the water volume.
Label concentration (%w/w): 50 Density (g/mL): 1.84 Molar mass (g/mol): 98.08 Target concentration: 1 M Final volume: 250 mL Show the answer and the working Measure 26.65 mL of the 50% stock (≈ 9.38 M) and dilute to 250 mL total.
Derive Stock molarity: M = (10 · %w/w · ρ) / MW Substitute label: M = (10 · 50 · 1.84) / 98.08 = 9.38 M Solve for Aliquot: V₁ = (C₂ · V₂) / C₁ Substitute: V₁ = (1 M · 250 mL) / (9.38 M) = 26.65 mL Diluent: V₂ − V₁ = 223.3 mL Open this in the calculator to change the numbers.
Problem 7 Acid / base dilution Work out the stock molarity, the acid aliquot, and the water volume.
Label concentration (%w/w): 15 Density (g/mL): 1.19 Molar mass (g/mol): 36.46 Target concentration: 1 M Final volume: 200 mL Show the answer and the working Measure 40.85 mL of the 15% stock (≈ 4.896 M) and dilute to 200 mL total.
Derive Stock molarity: M = (10 · %w/w · ρ) / MW Substitute label: M = (10 · 15 · 1.19) / 36.46 = 4.896 M Solve for Aliquot: V₁ = (C₂ · V₂) / C₁ Substitute: V₁ = (1 M · 200 mL) / (4.896 M) = 40.85 mL Diluent: V₂ − V₁ = 159.1 mL Open this in the calculator to change the numbers.
Problem 8 Acid / base dilution Work out the stock molarity, the acid aliquot, and the water volume.
Label concentration (%w/w): 30 Density (g/mL): 1.84 Molar mass (g/mol): 98.08 Target concentration: 4 M Final volume: 250 mL Show the answer and the working Measure 177.7 mL of the 30% stock (≈ 5.628 M) and dilute to 250 mL total.
Derive Stock molarity: M = (10 · %w/w · ρ) / MW Substitute label: M = (10 · 30 · 1.84) / 98.08 = 5.628 M Solve for Aliquot: V₁ = (C₂ · V₂) / C₁ Substitute: V₁ = (4 M · 250 mL) / (5.628 M) = 177.7 mL Diluent: V₂ − V₁ = 72.32 mL Open this in the calculator to change the numbers.
Problem 9 Acid / base dilution Work out the stock molarity, the acid aliquot, and the water volume.
Label concentration (%w/w): 15 Density (g/mL): 1.84 Molar mass (g/mol): 98.08 Target concentration: 1 M Final volume: 150 mL Show the answer and the working Measure 53.3 mL of the 15% stock (≈ 2.814 M) and dilute to 150 mL total.
Derive Stock molarity: M = (10 · %w/w · ρ) / MW Substitute label: M = (10 · 15 · 1.84) / 98.08 = 2.814 M Solve for Aliquot: V₁ = (C₂ · V₂) / C₁ Substitute: V₁ = (1 M · 150 mL) / (2.814 M) = 53.3 mL Diluent: V₂ − V₁ = 96.7 mL Open this in the calculator to change the numbers.
Problem 10 Acid / base dilution Work out the stock molarity, the acid aliquot, and the water volume.
Label concentration (%w/w): 30 Density (g/mL): 1.19 Molar mass (g/mol): 36.46 Target concentration: 1 M Final volume: 150 mL Show the answer and the working Measure 15.32 mL of the 30% stock (≈ 9.792 M) and dilute to 150 mL total.
Derive Stock molarity: M = (10 · %w/w · ρ) / MW Substitute label: M = (10 · 30 · 1.19) / 36.46 = 9.792 M Solve for Aliquot: V₁ = (C₂ · V₂) / C₁ Substitute: V₁ = (1 M · 150 mL) / (9.792 M) = 15.32 mL Diluent: V₂ − V₁ = 134.7 mL Open this in the calculator to change the numbers.
More dilutions practice
Same topic, different calculation C₁V₁ = C₂V₂, exactly how much stock and diluent to mix.
A fold-dilution series, tube by tube.
Stuck on one of them? Open it in the calculator and it shows the same working step by step, with the units checked and the hazards flagged. Free, no account, and it keeps working offline once the page has loaded.
Open the Acid / base dilution calculator