What you are given
- pKa: 8.06
- Target pH: 8
- Total concentration: 50 mM
Formula: pH = pKa + log₁₀([A⁻]/[HA])
pH = pKa + log10([A-]/[HA]). Rearranged, the base to acid ratio is 10^(pH - pKa). Split the total buffer concentration in that ratio to get the amount of each component.
Worked example
Formula: pH = pKa + log₁₀([A⁻]/[HA])
r = [A⁻]/[HA] = 10^(pH − pKa)r = 10^(8 − 8.06) = 0.871r / (1 + r) = 0.46551 / (1 + r) = 0.5345C_total · r/(1+r) = 50 mM · 0.4655 = 23.28 mMC_total · 1/(1+r) = 50 mM · 0.5345 = 26.72 mMFor pH 8, combine 23.28 mM conjugate base with 26.72 mM acid.
Source: Henderson-Hasselbalch equation. A printable one-page version is on the formula sheet.
Try it yourself
Work out the conjugate base and weak acid concentrations.
For pH 4.76, combine 100 mM conjugate base with 100 mM acid.
r = [A⁻]/[HA] = 10^(pH − pKa)r = 10^(4.76 − 4.76) = 1r / (1 + r) = 0.51 / (1 + r) = 0.5C_total · r/(1+r) = 200 mM · 0.5 = 100 mMC_total · 1/(1+r) = 200 mM · 0.5 = 100 mMOpen this in the calculator to change the numbers.
Work out the conjugate base and weak acid concentrations.
For pH 8, combine 4.655 mM conjugate base with 5.345 mM acid.
r = [A⁻]/[HA] = 10^(pH − pKa)r = 10^(8 − 8.06) = 0.871r / (1 + r) = 0.46551 / (1 + r) = 0.5345C_total · r/(1+r) = 10 mM · 0.4655 = 4.655 mMC_total · 1/(1+r) = 10 mM · 0.5345 = 5.345 mMOpen this in the calculator to change the numbers.
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